by JonCraig » Fri Mar 28, 2014 10:01 am
Thanks SO much for the links, guys. I'm looking at the wiring diagram, and I still can't quite figure this out.
Did I mention that I'm doing all this on the bench, with my own individual switches and not a proper keyswitch/ignition switch?
There are two red wires going into the wiring harness (marked "V" on page 34 of the service manual). I have my starter switch connected to the part of the harness that has TWO wires going into it. (That is to say, the factory Kohler harness has two wires going into the engine side of the connector.) One of them is the starter solenoid wire, marked "P" in the wiring diagram. The other is the "V" red wire. That (apparently) supplies +12V to the fuel solenoid (carb cutoff anti-backfire thing, if it's the same on Kohler as it is on the Briggs I'm used to).
One of the things I can't figure out is this… if that "V" red wire always has 12V applied to it, wouldn't that make the starter solenoid always hot, and thus constantly engage the starter? (Obviously that cannot be the case…).
I think my other question is related… There are two terminals on the starter… on one I have my large (6 gauge or so) cable from the batt + going to the starter. In the wiring diagram, that seems to be where the +12 from the regulator (marked "K"), along with one of the "V" wires, connects as well. (that connection goes through fuse "O" in the diagram, if it helps orient you.)
There ARE two marks in the jumble of colors coming out from the harness connector on the diagram, and they look like they MIGHT be diodes… and if they are, I think that makes some of this logic make sense, as I try to work through that thusly:
So if part "O" is connected to batt positive via being connected to that starter lug, that feeds thru the harness to the ignition switch. When the operator turns the switch to start, the switch sends +12 down the blue wire to the starter solenoid (simple enough), as well as down the top "V" wire to turn on the fuel solenoid. Once the motor is running, the operator lets go of the momentary start switch, which disengages the "P" (starter solenoid) wire, and instantly engages the lowest "V" red wire, which continues supplying +12 to the fuel solenoid. The diodes are in place to prevent exactly what I was talking about before--eliminating the +12V from constantly hitting the starter solenoid & engaging the starter.
SOOOO… if anyone was actually kind enough to follow through all that, does that make sense, or am I reading this totally wrong?
Almost forgot… so simply grounding "U" (which is also connected to "D" grrrr….) is the proper way to kill the ignition, yes?
Thanks in advance for helping me brush the cobwebs off my electronics minor back in college days!
--JC